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I search a little Script.
If a Player (With USGN in Script) say "@say Hello" the Hello is in Color with (Admin) but only when he say "@say".
Thanks you a lot !
iDios
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Scripts Color Say.
Color Say.
21 repliesI search a little Script.
If a Player (With USGN in Script) say "@say Hello" the Hello is in Color with (Admin) but only when he say "@say".
Thanks you a lot !
iDios
Use the "say" hook.
Use the string.sub function.
Use if txt:sub(1, 4) == "@say" then and use the msg function.
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Admin_Table = {}
RGBCLR = "255255255" -- Color for saying.
function table.find(tab,val)
for k, v in pairs(tab) do
if v == val then
return k
end
end
return false
end
addhook("say","onSay")
function onSay(id,txt)
if txt == "rank" then
return 0
end
if string.sub(txt,1,4) == "@say" then
txt = string.sub(txt,6)
if table.find(Admin_Table,player(id,"usgn")) then
msg("©"..RGBCLR..player(id,"name").." (Admin): "..txt)
return 1
end
end
end
In the admin table you have to put the USGN List, separed by comma.
Edit: forgot about the @say
Even if it's easy and you don't need much time, people have to learn themself, or they will ask again and again...
PS : Yasday, i'm not english, so it's too hard to learn...
would do it aswell, but only for one person.
Edit:
It's not to hard to learn, I'm german, not english and I did learn it.
edited 1×, last 16.04.11 05:20:22 pm
Cant you just do
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if (text == @say) then
msg("©255255255"..player(id,"name").." (Admin) "..txt)
Edit: Ah wait, must be with usgn aswell for the admin.. Meh can't be arsed to do that. But this should work either way?
string.sub returns the string from the point(s) you want, like string.sub("hi", 2, 2) returns "i".
Edit:
http://www.lua.org/manual/5.1/manual.html#pdf-string.sub
edited 1×, last 16.04.11 05:29:53 pm
"HELLO, MY NAME IS STARKKZ"
string.sub 1, 14 returns: "HELLO, MY NAME"
string.sub 16, 17 returns: "IS"
string.sub 19, 25 returns: "STARKKZ"
string.sub 1, 5 returns: "HELLO"
so thats useful to check the string..
with this method you can split strings too.. but i preefer string.gmatch
I understand why it would not work, but I have to learn more lua. Because I have no idea what you just said about string.sub
Yates has written
Ahh, lol. Not thinking straight.
I understand why it would not work, but I have to learn more lua. Because I have no idea what you just said about string.sub
I understand why it would not work, but I have to learn more lua. Because I have no idea what you just said about string.sub
Try this:
http://www.lua.org/manual/5.1/manual.html#pdf-string.sub
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addhook("say","what")
function what(id,txt)
if player(id,"name") then
msg("©255255255Citizen = "..player(id,"name").." : "..txt)
end
end
try if work 
thanks! 
You must put this © instead of the question mark in the lua.
Yates has written
Your name is "sh!t" I guess..
You must put this © instead of the question mark in the lua.
You must put this © instead of the question mark in the lua.
Thanks for help,but now I have new problem...
That is:
LUA ERROR: sys/lua/test.lua:1: unexpected symbol near 'ï'
LOL,I'm not edited anything in that script.
Admin_Table = {}
RGBCLR = "255255255" -- Color for saying.
function table.find(tab,val)
for k, v in pairs(tab) do
if v == val then
return k
end
end
return false
end
addhook("say","onSay")
function onSay(id,txt)
if txt == "rank" then
return 0
end
if string.sub(txt,1,4) == "@say" then
txt = string.sub(txt,6)
if table.find(Admin_Table,player(id,"usgn")) then
msg("©"..RGBCLR..player(id,"name").." (Admin): "..txt)
return 1
end
end
end
Whats indent? If its "tab" it, then:
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Admin_Table = {}
RGBCLR = "255255255" -- Color for saying.
function table.find(tab,val)
for k, v in pairs(tab) do
if v == val then
return k
end
end
return false
end
addhook("say","onSay")
function onSay(id,txt)
if txt == "rank" then
return 0
end
if string.sub(txt,1,4) == "@say" then
txt = string.sub(txt,6)
if table.find(Admin_Table,player(id,"usgn")) then
msg("©"..RGBCLR..player(id,"name").." (Admin): "..txt)
return 1
end
end
end